diff --git a/contents/solutions/AK106.md b/contents/solutions/AK106.md
index 8d68503..d7cb689 100644
--- a/contents/solutions/AK106.md
+++ b/contents/solutions/AK106.md
@@ -26,7 +26,7 @@ $P_\mathrm{EIRP} = \qty{100}{\watt} \cdot 10^{\frac{2{,}15 - 0{,}0}{10}} = \qty{
 
 2. Berechnung des Sicherheitsabstands $d$:
 
-$d = \frac{\sqrt{\qty{30}{\ohm} \cdot \qty{164,1}{\watt}}}{\qty{28}{\volt/\meter}} = \frac{\qty{70,2}{\volt}}{\qty{28}{\volt/\meter}} \approx \qty{2,50}{\meter}$
+$d = \frac{\sqrt{\qty{30}{\ohm} \cdot \qty{164,1}{\watt}}}{\qty{28}{\volt\per\meter}} = \frac{\qty{70,2}{\volt}}{\qty{28}{\volt\per\meter}} \approx \qty{2,50}{\meter}$
 
 3. Prüfung der Fernfeldbedingung: