From e265cc4c4aac97a3663988d4e2849bd777f9431c Mon Sep 17 00:00:00 2001
From: che0815 <elegantbreakdown@gmail.com>
Date: Sun, 27 Sep 2026 11:39:41 +0200
Subject: [PATCH 1/3] =?UTF-8?q?feature:=20Solution=20f=C3=BCr=20AB503?=
MIME-Version: 1.0
Content-Type: text/plain; charset=UTF-8
Content-Transfer-Encoding: 8bit

---
 contents/solutions/AB503.md | 20 ++++++++++++++++++++
 1 file changed, 20 insertions(+)
 create mode 100644 contents/solutions/AB503.md

diff --git a/contents/solutions/AB503.md b/contents/solutions/AB503.md
new file mode 100644
index 0000000..5c32198
--- /dev/null
+++ b/contents/solutions/AB503.md
@@ -0,0 +1,20 @@
+# Gegeben
+Spannung: $U = \qty{10}{\volt}$  
+Strom: $R = \qty{100}{\ohm}$  
+Dauer: $t = \qty{1}{\hour}$  
+
+# Lösungsweg
+Aus der Formelsammlung benötigen wir die Formel für die Energie (Arbeit):  
+
+$W = P \cdot t$
+
+und Leistung:  
+ 
+$P = \frac{U^2}{R}$
+
+Die Formeln ineinander einsetzen:
+
+$\rightarrow W = \frac{U^2}{R} \cdot t $
+
+Nun die gegebenen Werte einsetzen:  
+$\rightarrow W = \frac{\left(\qty{10}{\volt}\right)^2}{\qty{100}{\ohm}} \cdot\qty{1}{\hour}$
\ No newline at end of file

From 340bcaf31b587ce769565bf54ae195fc86c9f3d5 Mon Sep 17 00:00:00 2001
From: che0815 <elegantbreakdown@gmail.com>
Date: Sun, 27 Sep 2026 22:01:03 +0200
Subject: [PATCH 2/3] feature: solution for AB503

---
 contents/solutions/AB503.md | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/contents/solutions/AB503.md b/contents/solutions/AB503.md
index 5c32198..beb6cde 100644
--- a/contents/solutions/AB503.md
+++ b/contents/solutions/AB503.md
@@ -17,4 +17,4 @@ Die Formeln ineinander einsetzen:
 $\rightarrow W = \frac{U^2}{R} \cdot t $
 
 Nun die gegebenen Werte einsetzen:  
-$\rightarrow W = \frac{\left(\qty{10}{\volt}\right)^2}{\qty{100}{\ohm}} \cdot\qty{1}{\hour}$
\ No newline at end of file
+$\rightarrow W = \frac{\left(\qty{10}{\volt}\right)^2}{\qty{100}{\ohm}} \cdot\qty{1}{\hour}= \frac{\qty{100}{\volt^2}}{\qty{100}{\volt/\ampere}} \cdot\qty{1}{\hour}= \frac{\qty{100}{\volt\ampere\hour}}{100} = \qty{1}{\watt}$
\ No newline at end of file

From dc4194672e9de5bd854ba807ee401956c4005678 Mon Sep 17 00:00:00 2001
From: che0815 <elegantbreakdown@gmail.com>
Date: Sun, 4 Oct 2026 00:26:59 +0200
Subject: [PATCH 3/3] fix, refactor: Ws, alignment

---
 contents/solutions/AB503.md | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/contents/solutions/AB503.md b/contents/solutions/AB503.md
index beb6cde..155792d 100644
--- a/contents/solutions/AB503.md
+++ b/contents/solutions/AB503.md
@@ -17,4 +17,4 @@ Die Formeln ineinander einsetzen:
 $\rightarrow W = \frac{U^2}{R} \cdot t $
 
 Nun die gegebenen Werte einsetzen:  
-$\rightarrow W = \frac{\left(\qty{10}{\volt}\right)^2}{\qty{100}{\ohm}} \cdot\qty{1}{\hour}= \frac{\qty{100}{\volt^2}}{\qty{100}{\volt/\ampere}} \cdot\qty{1}{\hour}= \frac{\qty{100}{\volt\ampere\hour}}{100} = \qty{1}{\watt}$
\ No newline at end of file
+$\begin{align}\rightarrow W = \frac{\left(\qty{10}{\volt}\right)^2}{\qty{100}{\ohm}} \cdot\qty{1}{\hour} = \frac{\qty{100}{\volt\squared}}{\qty{100}{\volt\per\ampere}} \cdot\qty{1}{\hour} = \qty{\frac{100}{100}}{\volt\ampere} \cdot\qty{1}{\hour} &= \qty{1}{\volt\ampere}\cdot\qty{1}{\hour} = \qty{1}{\watt\hour}\\ &= \qty{1}{\volt\ampere}\cdot\qty{3600}{\second} = \qty{3600}{\watt\second} = \qty{3600}{\joule}\end{align}$
\ No newline at end of file