From eb00d095f8dea54872c60c7c0d5fdb63b177be69 Mon Sep 17 00:00:00 2001 From: Ralf Mahler Date: Tue, 16 Jun 2026 20:59:00 +0200 Subject: [PATCH] AK105.md angepasst qty --- contents/solutions/AK105.md | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) diff --git a/contents/solutions/AK105.md b/contents/solutions/AK105.md index 73f5554..2d262c2 100644 --- a/contents/solutions/AK105.md +++ b/contents/solutions/AK105.md @@ -16,7 +16,7 @@ $d = \frac{\sqrt{\qty{30}{\ohm} \cdot P_\mathrm{EIRP}}}{E}$ ## Einsetzen -$d_{{40}^\circ} = \frac{\sqrt{\qty{30}{\ohm} \cdot P_{{40}^\circ}}}{E} = \frac{\sqrt{\qty{30}{\ohm} \cdot 0,25 \cdot P_\mathrm{EIRP}}}{E} = \frac{\sqrt{0,25} \cdot \sqrt{\qty{30}{\ohm} \cdot P_\mathrm{EIRP}}}{E} = \sqrt{0,25} \cdot \frac{\sqrt{\qty{30}{\ohm} \cdot P_\mathrm{EIRP}}}{E} = 0,5 \cdot \frac{\sqrt{\qty{30}{\ohm} \cdot P_\mathrm{EIRP}}}{E} = 0,5 \cdot d$ +$d_{\qty{40}{^\circ}} = \frac{\sqrt{\qty{30}{\ohm} \cdot P_{\qty{40}{^\circ}}}}{E} = \frac{\sqrt{\qty{30}{\ohm} \cdot 0,25 \cdot P_\mathrm{EIRP}}}{E} = \frac{\sqrt{0,25} \cdot \sqrt{\qty{30}{\ohm} \cdot P_\mathrm{EIRP}}}{E} = \sqrt{0,25} \cdot \frac{\sqrt{\qty{30}{\ohm} \cdot P_\mathrm{EIRP}}}{E} = 0,5 \cdot \frac{\sqrt{\qty{30}{\ohm} \cdot P_\mathrm{EIRP}}}{E} = 0,5 \cdot d$ ## Interpretation der Formel