From f2b0145530da392e99e3fb9478fa86d789c7a95f Mon Sep 17 00:00:00 2001 From: che0815 Date: Mon, 23 Feb 2026 20:30:34 +0100 Subject: [PATCH] fix: repetition "also" --- contents/solutions/AA116.md | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) diff --git a/contents/solutions/AA116.md b/contents/solutions/AA116.md index 1de0114..79b0c10 100644 --- a/contents/solutions/AA116.md +++ b/contents/solutions/AA116.md @@ -3,7 +3,7 @@ * Genauigkeit: $\qty{10}{\ppm}$ # Lösungsweg -$\unit{ppm}$ steht für *parts per million*, $\qty{10}{\ppm}$ bedeutet also also $10$ pro $10^6$. +$\unit{ppm}$ steht für *parts per million*, $\qty{10}{\ppm}$ bedeutet also $10$ pro $10^6$. Die tatsächliche Sendefrequenz befindet sich zwischen $f_\text{min}$ und $f_\text{max}$. $f_\text{min} = f - 10 \cdot \frac{f}{10^6} = \qty{14,2}{\mega\hertz} - 10 \cdot \frac{14,2\cdot \qty{\cancel{10^6}}{\mega\hertz}}{\cancel{10^6}} = \qty{14,2}{\mega\hertz} - \qty{142}{\hertz} = \qty{14,199858}{\mega\hertz}$ $f_\text{max} = f + 10 \cdot \frac{f}{10^6} = \qty{14,2}{\mega\hertz} + 10 \cdot \frac{14,2\cdot \qty{\cancel{10^6}}{\mega\hertz}}{\cancel{10^6}} = \qty{14,2}{\mega\hertz} + \qty{142}{\hertz} = \qty{14,200142}{\mega\hertz}$ \ No newline at end of file