From 5a0dcd65b250eb041a34681cab3ec69a427408eb Mon Sep 17 00:00:00 2001 From: che0815 Date: Sun, 27 Sep 2026 11:15:06 +0200 Subject: [PATCH 1/3] =?UTF-8?q?feature:=20Solution=20f=C3=BCr=20AB502?= MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 8bit --- contents/solutions/AB502.md | 20 ++++++++++++++++++++ 1 file changed, 20 insertions(+) create mode 100644 contents/solutions/AB502.md diff --git a/contents/solutions/AB502.md b/contents/solutions/AB502.md new file mode 100644 index 0000000..36b2d47 --- /dev/null +++ b/contents/solutions/AB502.md @@ -0,0 +1,20 @@ +# Gegeben +Spannung: $U = \qty{230}{\volt}$ +Strom: $I = \qty{0,63}{\ampere}$ +Dauer: $t = \qty{7}{\hour}$ + +# Lösungsweg +Aus der Formelsammlung benötigen wir die Formel für die Energie (Arbeit): + +$W = P \cdot t$ + +und Leistung: + +$P = U \cdot I$ + +Die Formeln ineinander einsetzen: + +$\rightarrow W = U \cdot I \cdot t $ + +Nun die gegebenen Werte einsetzen: +$\rightarrow \qty{230}{\volt}\cdot \qty{0,63}{\ampere}\cdot\qty{7}{\hour} = \qty{1014,3}{\volt\ampere\hour} = \qty{1014,3}{\watt\hour} = \qty{1,01}{\kilo\watt\hour} $ \ No newline at end of file From 86ede80e5fec7a8d2cff4fd5e5d03552655328fe Mon Sep 17 00:00:00 2001 From: che0815 Date: Sun, 27 Sep 2026 11:41:06 +0200 Subject: [PATCH 2/3] fix: add W in last equation. --- contents/solutions/AB502.md | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) diff --git a/contents/solutions/AB502.md b/contents/solutions/AB502.md index 36b2d47..4f7ddcc 100644 --- a/contents/solutions/AB502.md +++ b/contents/solutions/AB502.md @@ -17,4 +17,4 @@ Die Formeln ineinander einsetzen: $\rightarrow W = U \cdot I \cdot t $ Nun die gegebenen Werte einsetzen: -$\rightarrow \qty{230}{\volt}\cdot \qty{0,63}{\ampere}\cdot\qty{7}{\hour} = \qty{1014,3}{\volt\ampere\hour} = \qty{1014,3}{\watt\hour} = \qty{1,01}{\kilo\watt\hour} $ \ No newline at end of file +$\rightarrow W = \qty{230}{\volt}\cdot \qty{0,63}{\ampere}\cdot\qty{7}{\hour} = \qty{1014,3}{\volt\ampere\hour} = \qty{1014,3}{\watt\hour} = \qty{1,01}{\kilo\watt\hour} $ \ No newline at end of file From dcc930018d194aea4f7b8a11e72186a7cc7cdb46 Mon Sep 17 00:00:00 2001 From: che0815 Date: Sun, 4 Oct 2026 00:21:11 +0200 Subject: [PATCH 3/3] fix: approx. --- contents/solutions/AB502.md | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) diff --git a/contents/solutions/AB502.md b/contents/solutions/AB502.md index 4f7ddcc..7260dab 100644 --- a/contents/solutions/AB502.md +++ b/contents/solutions/AB502.md @@ -17,4 +17,4 @@ Die Formeln ineinander einsetzen: $\rightarrow W = U \cdot I \cdot t $ Nun die gegebenen Werte einsetzen: -$\rightarrow W = \qty{230}{\volt}\cdot \qty{0,63}{\ampere}\cdot\qty{7}{\hour} = \qty{1014,3}{\volt\ampere\hour} = \qty{1014,3}{\watt\hour} = \qty{1,01}{\kilo\watt\hour} $ \ No newline at end of file +$\rightarrow W = \qty{230}{\volt}\cdot \qty{0,63}{\ampere}\cdot\qty{7}{\hour} = \qty{1014,3}{\volt\ampere\hour} = \qty{1014,3}{\watt\hour} \approx \qty{1,01}{\kilo\watt\hour}$ \ No newline at end of file