50ohm-contents-dl/contents/slides/transverter_2.md at f7fa8cfbc1188553d6e38d9321eabf7c2984ba94

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SuperminarenandClaude Sonnet 5.5 f7fa8cfbc1 Swedish adaptation: Instegscertifikat and HAREC content

- Sections and slides rewritten in Swedish; German law and institutions replaced by
  Swedish/CEPT/ITU equivalents (PTS, SSA, PTSFS 2025:1, SSMFS 2008:18), unverified
  statements marked "% TODO VERIFY"
- New toc: INSTEG, HAREC, UPPGRADERING; section idents are Swedish (see ident-map.tsv)
- Exam-question tags, BNetzA question pool, solutions and the German SWL course removed
- Static pages, snippets, applets, READMEs and image alt-texts translated
- TikZ labels translated; SVG drawings regenerated (drawing 689 still fails to build
  upstream: it references a missing photo)
- Changed from the original: not endorsed by DARC e.V., SSA or PTS

Co-Authored-By: Claude Sonnet 5.5 <noreply@anthropic.com>

2026-10-10 15:03:03 +02:00

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Omsättare från en frekvens till en annan med frekvensmultiplikatorer
Ligger oscillatorfrekvensen under nyttosignalen kan nyttosignalens högre frekvens blandas direkt till konverterns/transverterns högre utfrekvens
Ligger oscillatorfrekvensen över nyttosignalen inverteras en SSB-signal (USB \rightarrow LSB och LSB \rightarrow USB)

Lösningsgång

givet: \Delta f_\text{o} = \qty{440}{\mega\hertz} - \qty{30}{\mega\hertz} = \qty{410}{\mega\hertz}
givet: \Delta f_\text{u} = \qty{436}{\mega\hertz} - \qty{28}{\mega\hertz} = \qty{408}{\mega\hertz}
givet: n = 9
sökt: f_{\text{Osc},1}, f_{\text{Osc},2}

$f_{\text{Osc},1} = \frac{\Delta f_\text{u}}{n} = \frac{\qty{408}{\mega\hertz}}{9} = \qty{45,333}{\mega\hertz}$ $f_{\text{Osc},2} = \frac{\Delta f_\text{o}}{n} = \frac{\qty{410}{\mega\hertz}}{9} = \qty{45,556}{\mega\hertz}$ --- #### Lösningsgång * givet: $\Delta f_\text{o} = \qty{434}{\mega\hertz} - \qty{30}{\mega\hertz} = \qty{404}{\mega\hertz}$ * givet: $\Delta f_\text{u} = \qty{430}{\mega\hertz} - \qty{28}{\mega\hertz} = \qty{402}{\mega\hertz}$ * givet: $n = 9$ * sökt: $f_{\text{Osc},1}, f_{Osc,2}$ $f_{\text{Osc},1} = \frac{\Delta f_\text{u}}{n} = \frac{\qty{402}{\mega\hertz}}{9} = \qty{44,6667}{\mega\hertz}$ $f_{\text{Osc},2} = \frac{\Delta f_\text{o}}{n} = \frac{\qty{404}{\mega\hertz}}{9} = \qty{44,889}{\mega\hertz}$

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Lösningsgång

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