SuperminarenandClaude Sonnet 5.5
f7fa8cfbc1
- Sections and slides rewritten in Swedish; German law and institutions replaced by Swedish/CEPT/ITU equivalents (PTS, SSA, PTSFS 2025:1, SSMFS 2008:18), unverified statements marked "% TODO VERIFY" - New toc: INSTEG, HAREC, UPPGRADERING; section idents are Swedish (see ident-map.tsv) - Exam-question tags, BNetzA question pool, solutions and the German SWL course removed - Static pages, snippets, applets, READMEs and image alt-texts translated - TikZ labels translated; SVG drawings regenerated (drawing 689 still fails to build upstream: it references a missing photo) - Changed from the original: not endorsed by DARC e.V., SSA or PTS Co-Authored-By: Claude Sonnet 5.5 <noreply@anthropic.com>
27 lines
1.4 KiB
Markdown
27 lines
1.4 KiB
Markdown
* Omsättare från en frekvens till en annan med frekvensmultiplikatorer
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* Ligger oscillatorfrekvensen under nyttosignalen kan nyttosignalens högre frekvens blandas direkt till konverterns/transverterns högre utfrekvens
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* Ligger oscillatorfrekvensen över nyttosignalen inverteras en SSB-signal (USB $\rightarrow$ LSB och LSB $\rightarrow$ USB)
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---
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#### Lösningsgång
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* givet: $\Delta f_\text{o} = \qty{440}{\mega\hertz} - \qty{30}{\mega\hertz} = \qty{410}{\mega\hertz}$
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* givet: $\Delta f_\text{u} = \qty{436}{\mega\hertz} - \qty{28}{\mega\hertz} = \qty{408}{\mega\hertz}$
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* givet: $n = 9$
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* sökt: $f_{\text{Osc},1}, f_{\text{Osc},2}$
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<fragment>
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$f_{\text{Osc},1} = \frac{\Delta f_\text{u}}{n} = \frac{\qty{408}{\mega\hertz}}{9} = \qty{45,333}{\mega\hertz}$
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$f_{\text{Osc},2} = \frac{\Delta f_\text{o}}{n} = \frac{\qty{410}{\mega\hertz}}{9} = \qty{45,556}{\mega\hertz}$
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</fragment>
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---
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#### Lösningsgång
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* givet: $\Delta f_\text{o} = \qty{434}{\mega\hertz} - \qty{30}{\mega\hertz} = \qty{404}{\mega\hertz}$
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* givet: $\Delta f_\text{u} = \qty{430}{\mega\hertz} - \qty{28}{\mega\hertz} = \qty{402}{\mega\hertz}$
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* givet: $n = 9$
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* sökt: $f_{\text{Osc},1}, f_{Osc,2}$
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<fragment>
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$f_{\text{Osc},1} = \frac{\Delta f_\text{u}}{n} = \frac{\qty{402}{\mega\hertz}}{9} = \qty{44,6667}{\mega\hertz}$
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$f_{\text{Osc},2} = \frac{\Delta f_\text{o}}{n} = \frac{\qty{404}{\mega\hertz}}{9} = \qty{44,889}{\mega\hertz}$
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</fragment>
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